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author | Markus Teich <markus.teich@stusta.mhn.de> | 2016-10-15 20:31:37 +0200 |
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committer | Markus Teich <markus.teich@stusta.mhn.de> | 2016-10-15 20:31:37 +0200 |
commit | 5d028cc81ef0635a9dbf57584a1ac0dd3bb3cfb2 (patch) | |
tree | e4e095720de2507e356f70261316add44b905bb2 | |
parent | ca00e6ba8edc207aa4e296a796b9bc60ebc7c60f (diff) | |
download | libbrandt-5d028cc81ef0635a9dbf57584a1ac0dd3bb3cfb2.tar.gz libbrandt-5d028cc81ef0635a9dbf57584a1ac0dd3bb3cfb2.zip |
math.tex: fix M+1st private outcome function
-rw-r--r-- | tex-stuff/math.tex | 2 |
1 files changed, 1 insertions, 1 deletions
diff --git a/tex-stuff/math.tex b/tex-stuff/math.tex index 60568cf..929d658 100644 --- a/tex-stuff/math.tex +++ b/tex-stuff/math.tex | |||
@@ -227,7 +227,7 @@ The message has $nk$ parts, each consisting of $5$ Points. Therefore the message | |||
227 | is $5nk*32 = 160nk$ bytes large. | 227 | is $5nk*32 = 160nk$ bytes large. |
228 | 228 | ||
229 | $\forall i,j:$ Compute and publish \\[2.0ex] | 229 | $\forall i,j:$ Compute and publish \\[2.0ex] |
230 | $\gamma_{ij}^{\times a} = m_{ij}^{+a}\displaystyle\left(\sum_{h=1}^n\left(\sum_{d=j}^k\alpha_{hd}+\sum_{d=j+1}^k\alpha_{hd}\right)+\left(2M+2\right)\sum_{d=1}^{j}\alpha_{id} - \left(2M+1\right)Y \right)$ and \\[2.0ex] | 230 | $\gamma_{ij}^{\times a} = m_{ij}^{+a}\displaystyle\left(\sum_{h=1}^n\left(\sum_{d=j}^k\alpha_{hd}+\sum_{d=j+1}^k\alpha_{hd}\right)+\left(2M+2\right)\sum_{d=1}^{j}\alpha_{id} - \left(2M+1\right)G \right)$ and \\[2.0ex] |
231 | $\delta_{ij}^{\times a} = m_{ij}^{+a}\displaystyle\left(\sum_{h=1}^n\left(\sum_{d=j}^k \beta_{hd}+\sum_{d=j+1}^k \beta_{hd}\right)+\left(2M+2\right)\sum_{d=1}^{j} \beta_{id}\right)$ \\[2.0ex] | 231 | $\delta_{ij}^{\times a} = m_{ij}^{+a}\displaystyle\left(\sum_{h=1}^n\left(\sum_{d=j}^k \beta_{hd}+\sum_{d=j+1}^k \beta_{hd}\right)+\left(2M+2\right)\sum_{d=1}^{j} \beta_{id}\right)$ \\[2.0ex] |
232 | with a corresponding Proof 2 for $ECDL(\gamma_{ij}^{\times a}) = ECDL(\delta_{ij}^{\times a})$. | 232 | with a corresponding Proof 2 for $ECDL(\gamma_{ij}^{\times a}) = ECDL(\delta_{ij}^{\times a})$. |
233 | 233 | ||